(x+1)^2-3=(x-1)(x+1)

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Solution for (x+1)^2-3=(x-1)(x+1) equation: 



(x+1)^2-3=(x-1)(x+1)

We move all terms to the left:

(x+1)^2-3-((x-1)(x+1))=0

We use the square of the difference formula

x^2+(x+1)^2+1-3=0

We add all the numbers together, and all the variables

x^2+(x+1)^2-2=0

We move all terms containing x to the left, all other terms to the right

x^2+(x+1)^2=2

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